What is e^{-t}(cos(ω)t-2sin(ω)t) ?

The solution to e^{-t}(cos(ω)t-2sin(ω)t) is (tcos(ω)-2tsin(ω))/(e^t)

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simplify e^{-t}(cos(ω)t-2sin(ω)t)

simplify

e^{- t} (cos (ω) t - 2 sin (ω) t)

\frac{t cos ( ω ) - 2 t sin ( ω )}{e ^{t}}

Solution steps

e^{- t} (cos (ω) t - 2 sin (ω) t)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{t}} (t cos (ω) - 2 t sin (ω))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( cos ( ω ) t - 2 sin ( ω ) t )}{e ^{t}}

1 \cdot (cos (ω) t - 2 sin (ω) t) = t cos (ω) - 2 t sin (ω)

= \frac{t cos ( ω ) - 2 t sin ( ω )}{e ^{t}}

- 1.19 \cdot 8.333 x 1 0^{- 2}

e^{- 0.555}

(345) \cdot (85)

(e^{t}) (4 e^{t})

(e^{- x π})^{0}

What is e^{-t}(cos(ω)t-2sin(ω)t) ?
The solution to e^{-t}(cos(ω)t-2sin(ω)t) is (tcos(ω)-2tsin(ω))/(e^t)