What is (1.38*10^{-23})(77) ?

The solution to (1.38*10^{-23})(77) is (5313)/(50*10^{23)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (1.38*10^{-23})(77)

simplify

(1.38 \cdot 1 0^{- 23}) (77)

\frac{5313}{50 \cdot 1 0 ^{23}}

Decimal Notation

1.0626 E - 21

Solution steps

(1.38 \cdot 1 0^{- 23}) (77)

Apply rule:

(a) = a

(77) = 77

= 1.38 \cdot 1 0^{- 23} \cdot 77

Multiply the numbers:

1.38 \cdot 77 = 106.26

= 106.26 \cdot 1 0^{- 23}

= 1 0^{- 23} \cdot 106.26

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 23} = \frac{1}{1 0 ^{23}}

= \frac{1}{1 0 ^{23}} \cdot 106.26

\frac{1}{1 0 ^{23}} \cdot 106.26 = \frac{106.26}{1 0 ^{23}}

= \frac{106.26}{1 0 ^{23}}

\frac{106.26}{1 0 ^{23}} = \frac{10626}{100 \cdot 1 0 ^{23}}

= \frac{10626}{100 \cdot 1 0 ^{23}}

Factor the number:

10626 = 2 \cdot 5313

= \frac{2 \cdot 5313}{100 \cdot 1 0 ^{23}}

Factor the number:

100 = 2 \cdot 50

= \frac{2 \cdot 5313}{2 \cdot 50 \cdot 1 0 ^{23}}

Cancel the common factor:

2

= \frac{5313}{50 \cdot 1 0 ^{23}}

2 π (7.02 \cdot 1 0^{- 5}) (15)

4.11 x 1 0^{- 9}

2 e^{t} \cdot e^{- \frac{3 t}{2}}

(3 x^{5}) \cdot (5 x^{3})

((3 a)^{'})^{2} \cdot a^{2}

What is (1.38*10^{-23})(77) ?
The solution to (1.38*10^{-23})(77) is (5313)/(50*10^{23)}