What is 9e^{-kt}cos(wt) ?

The solution to 9e^{-kt}cos(wt) is (9cos(tw))/(e^{kt)}

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simplify 9e^{-kt}cos(wt)

simplify

9 e^{- k t} cos (wt)

\frac{9 cos ( tw )}{e ^{k t}}

Solution steps

9 e^{- k t} cos (wt)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 9 \cdot \frac{1}{e ^{k t}} cos (tw)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 9 cos ( wt )}{e ^{k t}}

Multiply the numbers:

1 \cdot 9 = 9

= \frac{9 cos ( tw )}{e ^{k t}}

30 e^{- 0.5 (5)}

28.8 \cdot 1 0^{- 4}

(0.5) \cdot v^{- 1}

What is 9e^{-kt}cos(wt) ?
The solution to 9e^{-kt}cos(wt) is (9cos(tw))/(e^{kt)}