What are the solutions to the equation 3t^2-t-6=0 ?

The solutions to the equation 3t^2-t-6=0 are t=(1+sqrt(73))/6 ,t=(1-sqrt(73))/6

Find the zeros of 3t^2-t-6=0

The zeros of 3t^2-t-6=0 are t=(1+sqrt(73))/6 ,t=(1-sqrt(73))/6

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3 t^{2} - t - 6 = 0

t = \frac{1 + 73}{6}, t = \frac{1 - 73}{6}

Decimal Notation

t = 1.59066 \dots, t = - 1.25733 \dots

Solution steps

3 t^{2} - t - 6 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 6) = 73

t_{1, 2} = \frac{- ( - 1 ) \pm 73}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 73}{2 \cdot 3}, t_{2} = \frac{- ( - 1 ) - 73}{2 \cdot 3}

t = \frac{- ( - 1 ) + 73}{2 \cdot 3} : \frac{1 + 73}{6}

t = \frac{- ( - 1 ) - 73}{2 \cdot 3} : \frac{1 - 73}{6}

The solutions to the quadratic equation are:

t = \frac{1 + 73}{6}, t = \frac{1 - 73}{6}

- 64 x^{3} + 125

- 17 < 1 - w

- 2 (5 + 6 n) < 6 (8 - 2 n)

\frac{3 x ^{5} y}{x ^{4} y ^{2}}

What are the solutions to the equation 3t^2-t-6=0 ?
The solutions to the equation 3t^2-t-6=0 are t=(1+sqrt(73))/6 ,t=(1-sqrt(73))/6
Find the zeros of 3t^2-t-6=0
The zeros of 3t^2-t-6=0 are t=(1+sqrt(73))/6 ,t=(1-sqrt(73))/6