What is e^4(\H(t-3)*e^{-1}) ?

The solution to e^4(\H(t-3)*e^{-1}) is e^3\H(t-3)

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simplify e^4(\H(t-3)*e^{-1})

simplify

e^{4} (H (t - 3) \cdot e^{- 1})

e^{3} H (t - 3)

Solution steps

e^{4} (H (t - 3) e^{- 1})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{4} e^{- 1} = e^{4 - 1}

= H (t - 3) e^{4 - 1}

Subtract the numbers:

4 - 1 = 3

= H (t - 3) e^{3}

25511428.57 \cdot 1 0^{- 9}

4.98 \cdot 1 0^{- 10} \cdot 2

e^{- 2 y} (4 e^{y} + c)