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Popular >

simplify 7x^34y^3y'(x)

Solution

simplify

7 x^{3} 4 y^{3} y^{'} (x)

Solution

28 x^{3} y^{3} y' (x)

Solution steps

7 x^{3} \cdot 4 y^{3} y^{'} (x)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{3} y^{3} = (x y)^{3}

= 7 \cdot 4 (x y)^{3} y^{^{'}} (x)

(x y)^{3} = x^{3} y^{3}

= 7 \cdot 4 x^{3} y^{3} y^{^{'}} (x)

Multiply the numbers:

7 \cdot 4 = 28

= 28 x^{3} y^{3} y^{^{'}} (x)

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20 e^{- 4 t}

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1.125 x 1 0^{- 3}

Frequently Asked Questions (FAQ)

What is 7x^34y^3y'(x) ?
The solution to 7x^34y^3y'(x) is 28x^3y^3y'(x)