What is 5x-4>= 12\lor 12x+5<=-4 ?

The solution to 5x-4>= 12\lor 12x+5 = 16/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5x-4>= 12\lor 12x+5<=-4

5 x - 4 \geq 12 or 12 x + 5 \leq - 4

x \leq - \frac{3}{4} or x \geq \frac{16}{5}

Interval Notation

(- \infty, - \frac{3}{4}] \cup [\frac{16}{5}, \infty)

Decimal Notation

x \leq - 0.75 or x \geq 3.2

Solution steps

5 x - 4 \geq 12 or 12 x + 5 \leq - 4

5 x - 4 \geq 12 : x \geq \frac{16}{5}

12 x + 5 \leq - 4 : x \leq - \frac{3}{4}

Combine the intervals

x \geq \frac{16}{5} or x \leq - \frac{3}{4}

Merge Overlapping Intervals

x \leq - \frac{3}{4} or x \geq \frac{16}{5}

- 16 = - 4 (v + 2)

\frac{1}{4 2}

- 2 (x - 3) = 8

∣ 5 a + 6 ∣ = ∣ 6 a - 8 ∣

20 x + 25 x^{2} + 4

What is 5x-4>= 12\lor 12x+5<=-4 ?
The solution to 5x-4>= 12\lor 12x+5<=-4 is x<=-3/4 \lor x>= 16/5