What is t^2(6t^{-4}ln(t)) ?

The solution to t^2(6t^{-4}ln(t)) is (6ln(t))/(t^2)

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simplify t^2(6t^{-4}ln(t))

simplify

t^{2} (6 t^{- 4} ln (t))

\frac{6 ln ( t )}{t ^{2}}

Solution steps

t^{2} (6 t^{- 4} ln (t))

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

t^{2} t^{- 4} = t^{2 - 4}

= 6 t^{2 - 4} ln (t)

Subtract the numbers:

2 - 4 = - 2

= 6 t^{- 2} ln (t)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

t^{- 2} = \frac{1}{t ^{2}}

= 6 \cdot \frac{1}{t ^{2}} ln (t)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 6 ln ( t )}{t ^{2}}

Multiply the numbers:

1 \cdot 6 = 6

= \frac{6 ln ( t )}{t ^{2}}

(a^{3} b^{3}) (a^{2} b^{3})

- 0.1874 \cdot 1.206 1^{- 0.02}

(2 x^{2}) (6 x)

2 x^{2} (2 y^{4})