What are the solutions to the equation x^2-10x+17=0 ?

The solutions to the equation x^2-10x+17=0 are x=5+2sqrt(2),x=5-2sqrt(2)

Find the zeros of x^2-10x+17=0

The zeros of x^2-10x+17=0 are x=5+2sqrt(2),x=5-2sqrt(2)

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x^{2} - 10 x + 17 = 0

x = 5 + 22, x = 5 - 22

Decimal Notation

x = 7.82842 \dots, x = 2.17157 \dots

Solution steps

x^{2} - 10 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 17 = 42

x_{1, 2} = \frac{- ( - 10 ) \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4 2}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4 2}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4 2}{2 \cdot 1} : 5 + 22

x = \frac{- ( - 10 ) - 4 2}{2 \cdot 1} : 5 - 22

The solutions to the quadratic equation are:

x = 5 + 22, x = 5 - 22

4 x + 5 = - 4 x + 5

∣ k + 7 ∣ = 3

3 - 2 x < x^{2}

- (x + h)^{2}

6 = 1 + 20 t - 5 t^{2}

What are the solutions to the equation x^2-10x+17=0 ?
The solutions to the equation x^2-10x+17=0 are x=5+2sqrt(2),x=5-2sqrt(2)
Find the zeros of x^2-10x+17=0
The zeros of x^2-10x+17=0 are x=5+2sqrt(2),x=5-2sqrt(2)