What is (m^2-m+1)^2(m^2+m+1)^2 ?

The solution to (m^2-m+1)^2(m^2+m+1)^2 is (m^2-m+1)^2(m^2+m+1)^2

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simplify (m^2-m+1)^2(m^2+m+1)^2

simplify

(m^{2} - m + 1)^{2} (m^{2} + m + 1)^{2}

(m^{2} - m + 1)^{2} (m^{2} + m + 1)^{2}

Solution steps

(m^{2} - m + 1)^{2} (m^{2} + m + 1)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(m^{2} - m + 1)^{2} (m^{2} + m + 1)^{2} = ((m^{2} - m + 1) (m^{2} + m + 1))^{2}

= ((m^{2} - m + 1) (m^{2} + m + 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (m^{2} - m + 1)^{2} (m^{2} + m + 1)^{2}

- 8.2 \cdot 1 0^{- 2}

20 e^{- 2 x}

(3 + 2 x)^{- 3}

(5.7 e^{- 5}) (4.56 e^{5})

0.005 (1 0^{- 15})

What is (m^2-m+1)^2(m^2+m+1)^2 ?
The solution to (m^2-m+1)^2(m^2+m+1)^2 is (m^2-m+1)^2(m^2+m+1)^2