What is 6x^{-0.75}(1+x) ?

The solution to 6x^{-0.75}(1+x) is (6(x+1))/(x^{0.75)}

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simplify 6x^{-0.75}(1+x)

simplify

6 x^{- 0.75} (1 + x)

\frac{6 ( x + 1 )}{x ^{0.75}}

Solution steps

6 x^{- 0.75} (1 + x)

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 6 \cdot \frac{1}{x ^{0.75}} (x + 1)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 6 ( 1 + x )}{x ^{0.75}}

Multiply the numbers:

1 \cdot 6 = 6

= \frac{6 ( x + 1 )}{x ^{0.75}}

12 \cdot 2.7 1^{- 2}

1.421 e^{- 9}

3 (e^{5})^{2}

4.06 \cdot 1 0^{- 8}

x^{- 1} (\frac{d y}{d x})

What is 6x^{-0.75}(1+x) ?
The solution to 6x^{-0.75}(1+x) is (6(x+1))/(x^{0.75)}