What are the solutions to the equation x^2-6x+7=0 ?

The solutions to the equation x^2-6x+7=0 are x=3+sqrt(2),x=3-sqrt(2)

Find the zeros of x^2-6x+7=0

The zeros of x^2-6x+7=0 are x=3+sqrt(2),x=3-sqrt(2)

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x^{2} - 6 x + 7 = 0

x = 3 + 2, x = 3 - 2

Solution steps

x^{2} - 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 7 = 22

x_{1, 2} = \frac{- ( - 6 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 2}{2 \cdot 1} : 3 + 2

x = \frac{- ( - 6 ) - 2 2}{2 \cdot 1} : 3 - 2

The solutions to the quadratic equation are:

x = 3 + 2, x = 3 - 2

x^{6} x^{9}

lo g_{2} (3) \cdot lo g_{3} (4)

3 (2 y - 4) - y = 5

3 x - 2 < x^{2}

\frac{t}{9} + 2 (\frac{t}{18} + 4) = 10

What are the solutions to the equation x^2-6x+7=0 ?
The solutions to the equation x^2-6x+7=0 are x=3+sqrt(2),x=3-sqrt(2)
Find the zeros of x^2-6x+7=0
The zeros of x^2-6x+7=0 are x=3+sqrt(2),x=3-sqrt(2)