What is (1/2)^{-ln(2x)} ?

The solution to (1/2)^{-ln(2x)} is 2^{ln(2x)}

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simplify (1/2)^{-ln(2x)}

simplify

(\frac{1}{2})^{- l n (2 x)}

2^{l n (2 x)}

Solution steps

(\frac{1}{2})^{- l n (2 x)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( \frac{1}{2} ) ^{l n (2 x)}}

(\frac{1}{2})^{l n (2 x)} = \frac{1 ^{l n (2 x)}}{2 ^{l n (2 x)}}

= \frac{1}{\frac{1 ^{l n (2 x)}}{2 ^{l n (2 x)}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{2 ^{l n (2 x)}}{1 ^{l n (2 x)}}

Apply exponent rule:

\frac{a ^{c}}{b ^{c}} = (\frac{a}{b})^{c}

= (\frac{2}{1})^{l n (2 x)}

Apply rule

\frac{a}{1} = a

\frac{2}{1} = 2

= 2^{l n (2 x)}

(2.456 x^{103}) x (4.2 x^{104})

e^{- 1 0^{6} \cdot 0}

6 e^{- \frac{1}{2}}

32 5^{4} \cdot 5.67 \cdot 1 0^{- 8}

53