What are the solutions to the equation 1/2 (x-1)^2+5=23 ?

The solutions to the equation 1/2 (x-1)^2+5=23 are x=7,x=-5

Find the zeros of 1/2 (x-1)^2+5=23

The zeros of 1/2 (x-1)^2+5=23 are x=7,x=-5

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\frac{1}{2} (x - 1)^{2} + 5 = 23

x = 7, x = - 5

Solution steps

\frac{1}{2} (x - 1)^{2} + 5 = 23

Move

5

to the right side

\frac{1}{2} (x - 1)^{2} = 18

Multiply both sides by

2

(x - 1)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 36 : x = 7

Solve

x - 1 = - 36 : x = - 5

The solutions to the quadratic equation are:

x = 7, x = - 5

27 x^{3} - 64 y^{3}

1 6^{\frac{- 2}{3}}

3 x + 3 = x + 7

\frac{7}{10} + \frac{3}{4}

2 x^{2} - 9 x + 4

What are the solutions to the equation 1/2 (x-1)^2+5=23 ?
The solutions to the equation 1/2 (x-1)^2+5=23 are x=7,x=-5
Find the zeros of 1/2 (x-1)^2+5=23
The zeros of 1/2 (x-1)^2+5=23 are x=7,x=-5