What is 2e^{-t/4 ln(2)} ?

The solution to 2e^{-t/4 ln(2)} is 2/(e^{\frac{ln(2)t){4}}}

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simplify 2e^{-t/4 ln(2)}

simplify

2 e^{- \frac{t}{4} l n (2)}

\frac{2}{e ^{\frac{l n ( 2 ) t}{4}}}

Solution steps

2 e^{- \frac{t}{4} l n (2)}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 2 \cdot \frac{1}{e ^{l n (2) \frac{t}{4}}}

\frac{1}{e ^{\frac{t}{4} l n (2)}} = \frac{1}{e ^{\frac{l n ( 2 ) t}{4}}}

= 2 \cdot \frac{1}{e ^{\frac{l n ( 2 ) t}{4}}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{e ^{\frac{t l n ( 2 )}{4}}}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{2}{e ^{\frac{t l n ( 2 )}{4}}}

(6 x^{10}) (3 x^{4})

- 4 (1.5)^{- 1}

9.107 \cdot 1 0^{- 31}

0.301 \cdot 1 0^{- 5}

- e^{- s t}

What is 2e^{-t/4 ln(2)} ?
The solution to 2e^{-t/4 ln(2)} is 2/(e^{\frac{ln(2)t){4}}}