What is (9.78x10^{-11})(3.4x10^{-18}) ?

The solution to (9.78x10^{-11})(3.4x10^{-18}) is (33.252x^2)/(10^{29)}

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simplify (9.78x10^{-11})(3.4x10^{-18})

simplify

(9.78 x 1 0^{- 11}) (3.4 x 1 0^{- 18})

\frac{33.252 x ^{2}}{1 0 ^{29}}

Solution steps

(9.78 x \cdot 1 0^{- 11}) (3.4 x \cdot 1 0^{- 18})

Simplify

9.78 x \cdot 1 0^{- 11} : \frac{9.78 x}{1 0 ^{11}}

= \frac{9.78 x}{1 0 ^{11}} \cdot 3.4 x \cdot 1 0^{- 18}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 18} = \frac{1}{1 0 ^{18}}

= \frac{9.78 x}{1 0 ^{11}} \cdot 3.4 x \frac{1}{1 0 ^{18}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{9.78 x \cdot 3.4 x \cdot 1}{1 0 ^{11} \cdot 1 0 ^{18}}

Simplify

9.78 x \cdot 3.4 x \cdot 1 : 33.252 x^{2}

= \frac{33.252 x ^{2}}{1 0 ^{11} \cdot 1 0 ^{18}}

1 0^{11} \cdot 1 0^{18} = 1 0^{29}

= \frac{33.252 x ^{2}}{1 0 ^{29}}

3.587 \cdot 1 0^{- 6} \cdot 1.449

100 \cdot e^{- 0.0105 \cdot 12}

- 1 \cdot e^{x^{- 2}} \cdot e^{x}

L^{10} e^{(- 4)}

What is (9.78x10^{-11})(3.4x10^{-18}) ?
The solution to (9.78x10^{-11})(3.4x10^{-18}) is (33.252x^2)/(10^{29)}