What are the solutions to the equation x^2+7x-3=-4x-21 ?

The solutions to the equation x^2+7x-3=-4x-21 are x=-2,x=-9

Find the zeros of x^2+7x-3=-4x-21

The zeros of x^2+7x-3=-4x-21 are x=-2,x=-9

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x^{2} + 7 x - 3 = - 4 x - 21

x = - 2, x = - 9

Solution steps

x^{2} + 7 x - 3 = - 4 x - 21

Move

21

to the left side

x^{2} + 7 x + 18 = - 4 x

Move

4 x

to the left side

x^{2} + 11 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 18 = 7

x_{1, 2} = \frac{- 11 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 7}{2 \cdot 1}, x_{2} = \frac{- 11 - 7}{2 \cdot 1}

x = \frac{- 11 + 7}{2 \cdot 1} : - 2

x = \frac{- 11 - 7}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = - 2, x = - 9

6 x^{2} - 5 x + 6 = 0

∣ x + 2 ∣ \leq 4

\frac{3}{4} q - \frac{2}{3} q < \frac{5}{12} q - \frac{1}{2}

5200

2 x + 2 = 10

What are the solutions to the equation x^2+7x-3=-4x-21 ?
The solutions to the equation x^2+7x-3=-4x-21 are x=-2,x=-9
Find the zeros of x^2+7x-3=-4x-21
The zeros of x^2+7x-3=-4x-21 are x=-2,x=-9