What is ((-1)^n)/((ln(n))^n) ?

The solution to ((-1)^n)/((ln(n))^n) is (-1/(ln(n)))^n

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simplify ((-1)^n)/((ln(n))^n)

simplify

\frac{( - 1 ) ^{n}}{( ln ( n ) ) ^{n}}

(- \frac{1}{ln ( n )})^{n}

Solution steps

\frac{( - 1 ) ^{n}}{( ln ( n ) ) ^{n}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{( - 1 ) ^{n}}{( ln ( n ) ) ^{n}} = (\frac{- 1}{ln ( n )})^{n}

= (\frac{- 1}{ln ( n )})^{n}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= (- \frac{1}{ln ( n )})^{n}

e^{- 100000000}

20000 (1 + \frac{0.02}{3})^{- 36}

\frac{e ^{-}}{e ^{- y - 2 x}}

(5 x^{2} y) (x^{3} y^{2})

What is ((-1)^n)/((ln(n))^n) ?
The solution to ((-1)^n)/((ln(n))^n) is (-1/(ln(n)))^n