What is (9*10^{-32})(15.8)(0.722) ?

The solution to (9*10^{-32})(15.8)(0.722) is (256671)/(2500*10^{32)}

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simplify (9*10^{-32})(15.8)(0.722)

simplify

(9 \cdot 1 0^{- 32}) (15.8) (0.722)

\frac{256671}{2500 \cdot 1 0 ^{32}}

Solution steps

(9 \cdot 1 0^{- 32}) (15.8) (0.722)

(9 \cdot 1 0^{- 32}) (15.8) (0.722) = (9 \cdot 1 0^{- 32}) \cdot 15.8 \cdot 0.722

= 9 \cdot 1 0^{- 32} \cdot 15.8 \cdot 0.722

Multiply the numbers:

9 \cdot 15.8 \cdot 0.722 = 102.6684

= 102.6684 \cdot 1 0^{- 32}

= 1 0^{- 32} \cdot 102.6684

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 32} = \frac{1}{1 0 ^{32}}

= \frac{1}{1 0 ^{32}} \cdot 102.6684

\frac{1}{1 0 ^{32}} \cdot 102.6684 = \frac{102.6684}{1 0 ^{32}}

= \frac{102.6684}{1 0 ^{32}}

\frac{102.6684}{1 0 ^{32}} = \frac{1026684}{10000 \cdot 1 0 ^{32}}

= \frac{1026684}{10000 \cdot 1 0 ^{32}}

Factor the number:

1026684 = 4 \cdot 256671

= \frac{4 \cdot 256671}{10000 \cdot 1 0 ^{32}}

Factor the number:

10000 = 4 \cdot 2500

= \frac{4 \cdot 256671}{4 \cdot 2500 \cdot 1 0 ^{32}}

Cancel the common factor:

4

= \frac{256671}{2500 \cdot 1 0 ^{32}}

e^{- 0.00271 \cdot 3200}

\frac{3 ^{100}}{7 ^{100}}

526.7 \cdot 4 \cdot 1 0^{- 6}

9.765 \cdot 1 0^{- 1}

2 x \cdot x - 20

What is (9*10^{-32})(15.8)(0.722) ?
The solution to (9*10^{-32})(15.8)(0.722) is (256671)/(2500*10^{32)}