What is e^{-2x}(8x^3-4x^4) ?

The solution to e^{-2x}(8x^3-4x^4) is (-4x^4+8x^3)/(e^{2x)}

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simplify e^{-2x}(8x^3-4x^4)

simplify

e^{- 2 x} (8 x^{3} - 4 x^{4})

\frac{- 4 x ^{4} + 8 x ^{3}}{e ^{2 x}}

Solution steps

e^{- 2 x} (8 x^{3} - 4 x^{4})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 x}} (- 4 x^{4} + 8 x^{3})

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 8 x ^{3} - 4 x ^{4} )}{e ^{2 x}}

1 \cdot (8 x^{3} - 4 x^{4}) = 8 x^{3} - 4 x^{4}

= \frac{8 x ^{3} - 4 x ^{4}}{e ^{2 x}}

8 x^{6} (4 x^{3})

(1.58 \cdot 1 0^{- 5}) \cdot 0.25

- 2 \cdot 2 + x

7.81 \cdot 1 0^{- 2}

23 w^{3} y^{6} w

What is e^{-2x}(8x^3-4x^4) ?
The solution to e^{-2x}(8x^3-4x^4) is (-4x^4+8x^3)/(e^{2x)}