What is the answer to 43(x+3)=78(3x+28)-5 ?

The answer to 43(x+3)=78(3x+28)-5 is x=-2050/191

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43(x+3)=78(3x+28)-5

43 (x + 3) = 78 (3 x + 28) - 5

x = - \frac{2050}{191}

Solution steps

43 (x + 3) = 78 (3 x + 28) - 5

Expand

43 (x + 3) : 43 x + 129

Expand

78 (3 x + 28) - 5 : 234 x + 2179

43 x + 129 = 234 x + 2179

Move

129

to the right side

43 x = 234 x + 2050

Move

234 x

to the left side

- 191 x = 2050

Divide both sides by

- 191

x = - \frac{2050}{191}

x^{3} - 5 x^{2} - x + 5 \geq 0

\frac{2}{m ^{2} n} + \frac{5}{n}

3 x^{2} + 2 x = 7

9 x^{2} - 6 x + 4 = 0

\frac{6 !}{5 ! 1 !}

What is the answer to 43(x+3)=78(3x+28)-5 ?
The answer to 43(x+3)=78(3x+28)-5 is x=-2050/191
Solve for x: 43(x+3)=78(3x+28)-5
The solution is x=-2050/191