What is [1-e^{x+y}]*[1-e^{x+y}] ?

The solution to [1-e^{x+y}]*[1-e^{x+y}] is (-e^{x+y}+1)^2

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simplify [1-e^{x+y}]*[1-e^{x+y}]

simplify

[1 - e^{x + y}] \cdot [1 - e^{x + y}]

(- e^{x + y} + 1)^{2}

Solution steps

[1 - e^{x + y}] [1 - e^{x + y}]

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

[1 - e^{x + y}] [1 - e^{x + y}] = (1 - e^{x + y})^{1 + 1}

= (1 - e^{x + y})^{1 + 1}

Add the numbers:

1 + 1 = 2

= (1 - e^{x + y})^{2}

\frac{1. 5 ^{2}}{0. 5 ^{2}}

25 \cdot π \cdot 1 0^{- 4}

(2 x^{5} y) (x^{4} y)

e^{- 46.11}

(2 π \cdot 60) (10 \cdot 1 0^{- 9})

What is [1-e^{x+y}]*[1-e^{x+y}] ?
The solution to [1-e^{x+y}]*[1-e^{x+y}] is (-e^{x+y}+1)^2