What are the solutions to the equation -2x^2+x+6=0 ?

The solutions to the equation -2x^2+x+6=0 are x=-3/2 ,x=2

Find the zeros of -2x^2+x+6=0

The zeros of -2x^2+x+6=0 are x=-3/2 ,x=2

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- 2 x^{2} + x + 6 = 0

x = - \frac{3}{2}, x = 2

Solution steps

- 2 x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 6 = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 ( - 2 )}, x_{2} = \frac{- 1 - 7}{2 ( - 2 )}

x = \frac{- 1 + 7}{2 ( - 2 )} : - \frac{3}{2}

x = \frac{- 1 - 7}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 2

3 - 2 x - x^{2}

4 (3 h - 11) < 6 (2 h - 3) + 19

x^{2} + 2 x + (6 - 3) 2 = 0

4 y^{2} + 7 y - 2

5 x^{2} - 6 x - 8

What are the solutions to the equation -2x^2+x+6=0 ?
The solutions to the equation -2x^2+x+6=0 are x=-3/2 ,x=2
Find the zeros of -2x^2+x+6=0
The zeros of -2x^2+x+6=0 are x=-3/2 ,x=2