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Popular >

simplify (e^{ln(1+0.133592)})^5

Solution

simplify

(e^{l n (1 + 0.133592)})^{5}

Solution

1.87190 \dots

Solution steps

(e^{l n (1 + 0.133592)})^{5}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= e^{l n (1 + 0.133592) \cdot 5}

ln (1 + 0.133592) \cdot 5 = 0.62695 \dots

= e^{0.62695 \dots}

e^{0.62695 \dots} = 1.87190 \dots

= 1.87190 \dots

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Frequently Asked Questions (FAQ)

What is (e^{ln(1+0.133592)})^5 ?
The solution to (e^{ln(1+0.133592)})^5 is 1.87190…