What is (e^{(-1)/(x^2)})^{(n)} ?

The solution to (e^{(-1)/(x^2)})^{(n)} is e^{-n/(x^2)}

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simplify (e^{(-1)/(x^2)})^{(n)}

simplify

(e^{\frac{- 1}{x ^{2}}})^{(n)}

e^{- \frac{n}{x ^{2}}}

Solution steps

(e^{\frac{- 1}{x ^{2}}})^{(n)}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= e^{\frac{- 1}{x ^{2}} n}

Simplify

\frac{- 1}{x ^{2}} n : - \frac{n}{x ^{2}}

= e^{- \frac{n}{x ^{2}}}

5 e \cdot e^{x}

(3 x^{3} y^{3}) (2 y^{3})

3.48 \cdot 1 0^{- 3}

(7 u + 1)^{2} (7 u - 1)^{2}

1.87 \cdot 1 0^{- 3}

What is (e^{(-1)/(x^2)})^{(n)} ?
The solution to (e^{(-1)/(x^2)})^{(n)} is e^{-n/(x^2)}