What are the solutions to the equation 4x^2+3x-6=0 ?

The solutions to the equation 4x^2+3x-6=0 are x=(-3+sqrt(105))/8 ,x=(-3-sqrt(105))/8

Find the zeros of 4x^2+3x-6=0

The zeros of 4x^2+3x-6=0 are x=(-3+sqrt(105))/8 ,x=(-3-sqrt(105))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 3 x - 6 = 0

x = \frac{- 3 + 105}{8}, x = \frac{- 3 - 105}{8}

Decimal Notation

x = 0.90586 \dots, x = - 1.65586 \dots

Solution steps

4 x^{2} + 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 6) = 105

x_{1, 2} = \frac{- 3 \pm 105}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 105}{2 \cdot 4}, x_{2} = \frac{- 3 - 105}{2 \cdot 4}

x = \frac{- 3 + 105}{2 \cdot 4} : \frac{- 3 + 105}{8}

x = \frac{- 3 - 105}{2 \cdot 4} : \frac{- 3 - 105}{8}

The solutions to the quadratic equation are:

x = \frac{- 3 + 105}{8}, x = \frac{- 3 - 105}{8}

(2 x + 3)^{2} + 25 = 0

(\frac{1}{4})^{1}

- 5 x + 12 = - 12 x - 12

\frac{( \frac{a}{b} )}{c} + \frac{d}{( \frac{e}{f} )}

27 x^{3} - 12 x

What are the solutions to the equation 4x^2+3x-6=0 ?
The solutions to the equation 4x^2+3x-6=0 are x=(-3+sqrt(105))/8 ,x=(-3-sqrt(105))/8
Find the zeros of 4x^2+3x-6=0
The zeros of 4x^2+3x-6=0 are x=(-3+sqrt(105))/8 ,x=(-3-sqrt(105))/8