What is (1/2)^ne^{-n} ?

The solution to (1/2)^ne^{-n} is 1/(2^ne^n)

Popular >

simplify (1/2)^ne^{-n}

simplify

(\frac{1}{2})^{n} e^{- n}

\frac{1}{2 ^{n} e ^{n}}

Solution steps

(\frac{1}{2})^{n} e^{- n}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{n}} (\frac{1}{2})^{n}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( \frac{1}{2} ) ^{n}}{e ^{n}}

Multiply:

1 \cdot (\frac{1}{2})^{n} = (\frac{1}{2})^{n}

= \frac{( \frac{1}{2} ) ^{n}}{e ^{n}}

(\frac{1}{2})^{n} = \frac{1}{2 ^{n}}

= \frac{\frac{1}{2 ^{n}}}{e ^{n}}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{1}{2 ^{n} e ^{n}}

1021 (1.6 \cdot 1 0^{- 19})

x (a x^{b - 1} y^{1 - b})

(e^{- \frac{l n ( x )}{2}})^{2}

2^{- 5 \circ} 2^{3}

(1.52 x 1 0^{- 12}) (4.9 x 1 0^{- 8})