What are the solutions to the equation 3x^2-2x=2x^2-4x ?

The solutions to the equation 3x^2-2x=2x^2-4x are x=0,x=-2

Find the zeros of 3x^2-2x=2x^2-4x

The zeros of 3x^2-2x=2x^2-4x are x=0,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 2 x = 2 x^{2} - 4 x

x = 0, x = - 2

Solution steps

3 x^{2} - 2 x = 2 x^{2} - 4 x

Move

4 x

to the left side

3 x^{2} + 2 x = 2 x^{2}

Move

2 x^{2}

to the left side

x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 \cdot 1}, x_{2} = \frac{- 2 - 2}{2 \cdot 1}

x = \frac{- 2 + 2}{2 \cdot 1} : 0

x = \frac{- 2 - 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

\frac{x ^{2} + 3 x + 2}{x + 1} \geq 0

- \frac{v}{6} > - 2

3 - x + 4 = - x + 7

150 + m = 360

What are the solutions to the equation 3x^2-2x=2x^2-4x ?
The solutions to the equation 3x^2-2x=2x^2-4x are x=0,x=-2
Find the zeros of 3x^2-2x=2x^2-4x
The zeros of 3x^2-2x=2x^2-4x are x=0,x=-2