What is h(x)1.4^{-x^2} ?

The solution to h(x)1.4^{-x^2} is (hx)/(1.4^{x^2)}

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simplify h(x)1.4^{-x^2}

simplify

h (x) 1. 4^{- x^{2}}

\frac{h x}{1. 4 ^{x^{2}}}

Solution steps

h (x) \cdot 1. 4^{- x^{2}}

Apply rule:

(a) = a

(x) = x

= h x \cdot 1. 4^{- x^{2}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

1. 4^{- x^{2}} = \frac{1}{1. 4 ^{x^{2}}}

= h x \frac{1}{1. 4 ^{x^{2}}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{h x \cdot 1}{1. 4 ^{x^{2}}}

Apply rule:

a \cdot 1 = a

h x \cdot 1 = h x

= \frac{h x}{1. 4 ^{x^{2}}}

5 e^{- 10}

32 x^{2} y^{2} x y

8.97 \cdot 1 0^{- 7}

3^{- 666}