What is e^{-3ln((y-1)/(y+1))} ?

The solution to e^{-3ln((y-1)/(y+1))} is ((y+1)^3)/((y-1)^3)

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simplify e^{-3ln((y-1)/(y+1))}

simplify

e^{- 3 l n (\frac{y - 1}{y + 1})}

\frac{( y + 1 ) ^{3}}{( y - 1 ) ^{3}}

Solution steps

e^{- 3 l n (\frac{y - 1}{y + 1})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{3 l n (\frac{y - 1}{y + 1})}}

e^{3 l n (\frac{y - 1}{y + 1})} = \frac{( y - 1 ) ^{3}}{( y + 1 ) ^{3}}

= \frac{1}{\frac{( y - 1 ) ^{3}}{( y + 1 ) ^{3}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{( y + 1 ) ^{3}}{( y - 1 ) ^{3}}

2 e^{- 2 t s i n (2 t)}

I n (I n e^{e^{200}})

8.8 e^{- 10}

9.995 x 1 0^{- 3}

0.18 \cdot 9.8 \cdot 1 0^{- 3}

What is e^{-3ln((y-1)/(y+1))} ?
The solution to e^{-3ln((y-1)/(y+1))} is ((y+1)^3)/((y-1)^3)