What are the solutions to the equation 2z^2+20z=0 ?

The solutions to the equation 2z^2+20z=0 are z=0,z=-10

Find the zeros of 2z^2+20z=0

The zeros of 2z^2+20z=0 are z=0,z=-10

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2 z^{2} + 20 z = 0

z = 0, z = - 10

Solution steps

2 z^{2} + 20 z = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 \cdot 0 = 20

z_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- 20 + 20}{2 \cdot 2}, z_{2} = \frac{- 20 - 20}{2 \cdot 2}

z = \frac{- 20 + 20}{2 \cdot 2} : 0

z = \frac{- 20 - 20}{2 \cdot 2} : - 10

The solutions to the quadratic equation are:

z = 0, z = - 10

r^{2} + 5 r

(\frac{1}{6})^{- 3}

- 0.5 + \frac{5}{8}

17 - 6 x \geq 4 x - 10

- \frac{\frac{4}{5}}{( - \frac{8}{15} )}

What are the solutions to the equation 2z^2+20z=0 ?
The solutions to the equation 2z^2+20z=0 are z=0,z=-10
Find the zeros of 2z^2+20z=0
The zeros of 2z^2+20z=0 are z=0,z=-10