What is 3(x^2+2x)0.3(x^2+2x) ?

The solution to 3(x^2+2x)0.3(x^2+2x) is 0.9(x^2+2x)^2

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simplify 3(x^2+2x)0.3(x^2+2x)

simplify

3 (x^{2} + 2 x) 0.3 (x^{2} + 2 x)

0.9 (x^{2} + 2 x)^{2}

Solution steps

3 (x^{2} + 2 x) \cdot 0.3 (x^{2} + 2 x)

Multiply the numbers:

3 \cdot 0.3 = 0.9

= 0.9 (x^{2} + 2 x) (x^{2} + 2 x)

Apply exponent rule:

aa = a^{2}

(x^{2} + 2 x) (x^{2} + 2 x) = (x^{2} + 2 x)^{2}

= 0.9 (x^{2} + 2 x)^{2}

(3 (3 a^{2} - 2 y))^{2}

5.183 \cdot 1 0^{- 4}

e^{- (- l n (0.5))^{0.5}}

y + 1 2 y + 1

284.9 \cdot 1 0^{- 4}

What is 3(x^2+2x)0.3(x^2+2x) ?
The solution to 3(x^2+2x)0.3(x^2+2x) is 0.9(x^2+2x)^2