What is the general solution for roots cos^2(x)sin^2(y) ?

The general solution for roots cos^2(x)sin^2(y) is x= pi/2+2pin,x=(3pi)/2+2pin,y=2pin,y=pi+2pin

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roots cos^2(x)sin^2(y)

roots

cos^{2} (x) sin^{2} (y)

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, y = 2 πn, y = π + 2 πn

Solution steps

cos^{2} (x) sin^{2} (y)

The roots are the intercepts with the x-axis

(y = 0)

cos^{2} (x) sin^{2} (y) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

cos^{2} (x) = 0 or sin^{2} (y) = 0

Solve

cos^{2} (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solve

sin^{2} (y) = 0 : y = 2 πn, y = π + 2 πn

The solutions are

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn, y = 2 πn, y = π + 2 πn

32 \cdot e^{- 3}

e^{x} (\frac{1}{2} e^{2 x})

2.32 \cdot 1 0^{- 6}

f (x) = cos^{2} (x) sin^{2} (x)

2.32 \cdot 1 0^{- 4}

What is the general solution for roots cos^2(x)sin^2(y) ?
The general solution for roots cos^2(x)sin^2(y) is x= pi/2+2pin,x=(3pi)/2+2pin,y=2pin,y=pi+2pin