What is expand (2(-d+1))^{1-d} ?

The solution to expand (2(-d+1))^{1-d} is 2^{-d+1}(-d+1)^{-d+1}

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expand (2(-d+1))^{1-d}

expand

(2 (- d + 1))^{1 - d}

2^{- d + 1} (- d + 1)^{- d + 1}

Solution steps

(2 (- d + 1))^{1 - d}

Apply exponent rule:

(ab)^{c} = a^{c} b^{c}

(2 (- d + 1))^{1 - d} = 2^{1 - d} (- d + 1)^{1 - d}

= 2^{- d + 1} (- d + 1)^{- d + 1}

3.17 \cdot 1 0^{- 6}

\frac{e ^{6}}{e ^{9}}

4.16 \cdot 1 0^{- 9} \cdot 1000

(x^{- 4}) x^{5} e^{x}

6.45 \cdot 1 0^{- 2}

What is expand (2(-d+1))^{1-d} ?
The solution to expand (2(-d+1))^{1-d} is 2^{-d+1}(-d+1)^{-d+1}