What is (27a^nb^m)(2a^nb) ?

The solution to (27a^nb^m)(2a^nb) is 54a^{2n}b^{m+1}

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simplify (27a^nb^m)(2a^nb)

simplify

(27 a^{n} b^{m}) (2 a^{n} b)

54 a^{2 n} b^{m + 1}

Solution steps

(27 a^{n} b^{m}) (2 a^{n} b)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

a^{n} a^{n} = a^{n + n}

= 27 b^{m} \cdot 2 a^{n + n} b

Add similar elements:

n + n = 2 n

= 27 b^{m} \cdot 2 a^{2 n} b

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

b^{m} b = b^{m + 1}

= 27 \cdot 2 a^{2 n} b^{m + 1}

Multiply the numbers:

27 \cdot 2 = 54

= 54 a^{2 n} b^{m + 1}

\frac{e ^{2}}{( 2 - 2 ) ^{2}}

3 e^{- 3 \cdot 14}

50 e^{- 0.34657 \cdot 4}

What is (27a^nb^m)(2a^nb) ?
The solution to (27a^nb^m)(2a^nb) is 54a^{2n}b^{m+1}