What is sqrt(3x+1)sqrt(x+1=2) ?

The solution to sqrt(3x+1)sqrt(x+1=2) is sqrt((3x+1)(x+1*2=))

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simplify sqrt(3x+1)sqrt(x+1=2)

simplify

3 x + 1 x + 1 = 2

(3 x + 1) (x + 1 \cdot 2 =)

Solution steps

3 x + 1 x + 1 = 2

Apply radical rule:

a b = a \cdot b,

assuming

a \geq 0, b \geq 0

3 x + 1 x + 1 \cdot 2 = = (3 x + 1) (x + 1 \cdot 2 =)

= (3 x + 1) (x + 1 \cdot 2 =)

4.39 \cdot 1 0^{- 6}

12.4 \cdot 1 0^{- 1}

t e^{(- a t)}

7.25 \cdot 1 0^{- 30}

e^{- 4} \frac{4 ^{0}}{1}

What is sqrt(3x+1)sqrt(x+1=2) ?
The solution to sqrt(3x+1)sqrt(x+1=2) is sqrt((3x+1)(x+1*2=))