What is (80,tooth)(output^{40}tooth) ?

The solution to (80,tooth)(output^{40}tooth) is t^{43}o^3hu^2p(80,ttooh)

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simplify (80,tooth)(output^{40}tooth)

simplify

(80, t oo t h) (o u tp u t^{40} t oo t h)

t^{43} o^{3} h u^{2} p (80, tt oo h)

Solution steps

(80, t oo t h) (o u tp u t^{40} t oo t h)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

t t^{40} tt = t^{1 + 40 + 1 + 1}

= (80, t oo t h) o u p u oo t^{1 + 40 + 1 + 1} h

Add the numbers:

1 + 40 + 1 + 1 = 43

= (80, t oo t h) o u p u oo t^{43} h

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ooo = o^{1 + 1 + 1}

= (80, t oo t h) u p u o^{1 + 1 + 1} t^{43} h

Add the numbers:

1 + 1 + 1 = 3

= (80, t oo t h) u p u o^{3} t^{43} h

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

uu = u^{1 + 1}

= (80, t oo t h) p u^{1 + 1} o^{3} t^{43} h

Add the numbers:

1 + 1 = 2

= (80, t oo t h) p u^{2} o^{3} t^{43} h

(1 \cdot 1 0^{- 13}) \frac{4}{3} π

- e^{- 0.05 (12)}

e^{- \frac{r}{r}}

((2^{3})^{3})^{2}

What is (80,tooth)(output^{40}tooth) ?
The solution to (80,tooth)(output^{40}tooth) is t^{43}o^3hu^2p(80,ttooh)