What are the solutions to the equation 6v^2-6v-7=0 ?

The solutions to the equation 6v^2-6v-7=0 are v=(3+sqrt(51))/6 ,v=(3-sqrt(51))/6

Find the zeros of 6v^2-6v-7=0

The zeros of 6v^2-6v-7=0 are v=(3+sqrt(51))/6 ,v=(3-sqrt(51))/6

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6 v^{2} - 6 v - 7 = 0

v = \frac{3 + 51}{6}, v = \frac{3 - 51}{6}

Decimal Notation

v = 1.69023 \dots, v = - 0.69023 \dots

Solution steps

6 v^{2} - 6 v - 7 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 6 ( - 7 )}{2 \cdot 6}

(- 6)^{2} - 4 \cdot 6 (- 7) = 251

v_{1, 2} = \frac{- ( - 6 ) \pm 2 51}{2 \cdot 6}

Separate the solutions

v_{1} = \frac{- ( - 6 ) + 2 51}{2 \cdot 6}, v_{2} = \frac{- ( - 6 ) - 2 51}{2 \cdot 6}

v = \frac{- ( - 6 ) + 2 51}{2 \cdot 6} : \frac{3 + 51}{6}

v = \frac{- ( - 6 ) - 2 51}{2 \cdot 6} : \frac{3 - 51}{6}

The solutions to the quadratic equation are:

v = \frac{3 + 51}{6}, v = \frac{3 - 51}{6}

(\frac{3}{3 2 ^{\frac{2}{5}}})^{\frac{1}{2}}

⌈ 0 ⌉

\frac{5}{8} - \frac{3}{20}

3 \cdot x^{2} + x - 2 = 0

- 6 (3 n - 2) = 4 (- 3 - 2 n)

What are the solutions to the equation 6v^2-6v-7=0 ?
The solutions to the equation 6v^2-6v-7=0 are v=(3+sqrt(51))/6 ,v=(3-sqrt(51))/6
Find the zeros of 6v^2-6v-7=0
The zeros of 6v^2-6v-7=0 are v=(3+sqrt(51))/6 ,v=(3-sqrt(51))/6