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Popular >

simplify e^{-(x-1+ln(x-1))}

Solution

simplify

e^{- (x - 1 + l n (x - 1))}

Solution

\frac{1}{e ^{x - 1} ( x - 1 )}

Solution steps

e^{- (x - 1 + l n (x - 1))}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{(x - 1 + l n (x - 1))}}

Remove parentheses:

(a) = a

= \frac{1}{e ^{x - 1 + l n (x - 1)}}

e^{x - 1 + l n (x - 1)} = e^{x - 1} (x - 1)

= \frac{1}{e ^{x - 1} ( x - 1 )}

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Frequently Asked Questions (FAQ)

What is e^{-(x-1+ln(x-1))} ?
The solution to e^{-(x-1+ln(x-1))} is 1/(e^{x-1)(x-1)}