What is sqrt(3^2+(75.2-2659))^2 ?

The solution to sqrt(3^2+(75.2-2659))^2 is -12874/5

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simplify sqrt(3^2+(75.2-2659))^2

simplify

3^{2} + (75.2 - 2659)^{2}

- \frac{12874}{5}

Decimal Notation

- 2574.8

Solution steps

(3^{2} + (75.2 - 2659))^{2}

Apply rule:

a + (b + c) = a + b + c

3^{2} + (75.2 - 2659) = 3^{2} + 75.2 - 2659

= (3^{2} + 75.2 - 2659)^{2}

3^{2} + 75.2 - 2659 = \frac{12874}{5} i

= (\frac{12874}{5} i)^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(\frac{12874}{5} i)^{2} = (\frac{12874}{5})^{2} i^{2}

= (\frac{12874}{5})^{2} i^{2}

(\frac{12874}{5})^{2} = \frac{12874}{5}

= \frac{12874}{5} i^{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{12874 i ^{2}}{5}

Simplify

12874 i^{2} : - 12874

= \frac{- 12874}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{12874}{5}

x (x - 2)^{2} (2 x - 1)^{2}

(x^{- 3} y^{3})^{- 7^{^{'}}}

e^{- 0.007 \cdot 200}

- e^{- \frac{525}{5}}

7.055 \cdot 1 0^{- 3}

What is sqrt(3^2+(75.2-2659))^2 ?
The solution to sqrt(3^2+(75.2-2659))^2 is -12874/5