What is (sqrt(2sin(2θ)))^3 ?

The solution to (sqrt(2sin(2θ)))^3 is 2sqrt(2)sin^{3/2}(2θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (sqrt(2sin(2θ)))^3

simplify

(2 sin (2 θ))^{3}

22 sin^{\frac{3}{2}} (2 θ)

Solution steps

(2 sin (2 θ))^{3}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((2 sin (2 θ))^{\frac{1}{2}})^{3}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (2 sin (2 θ))^{\frac{1}{2} \cdot 3}

\frac{1}{2} \cdot 3 = \frac{3}{2}

= (2 sin (2 θ))^{\frac{3}{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= 2^{\frac{3}{2}} sin^{\frac{3}{2}} (2 θ)

2^{\frac{3}{2}} = 22

= 22 sin^{\frac{3}{2}} (2 θ)

0.388 \cdot 1 0^{- 3}

(4 x^{3} y^{5}) (10 x)

2^{x} \cdot e^{x}

lo g_{10} (1.75 x) 1 0^{- 15}

(5 x + 4)^{2} (5 x - 4)^{2}

What is (sqrt(2sin(2θ)))^3 ?
The solution to (sqrt(2sin(2θ)))^3 is 2sqrt(2)sin^{3/2}(2θ)