What are the solutions to the equation 8r^2-9r-3=0 ?

The solutions to the equation 8r^2-9r-3=0 are r=(9+sqrt(177))/(16),r=(9-sqrt(177))/(16)

Find the zeros of 8r^2-9r-3=0

The zeros of 8r^2-9r-3=0 are r=(9+sqrt(177))/(16),r=(9-sqrt(177))/(16)

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8 r^{2} - 9 r - 3 = 0

r = \frac{9 + 177}{16}, r = \frac{9 - 177}{16}

Solution steps

8 r^{2} - 9 r - 3 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

(- 9)^{2} - 4 \cdot 8 (- 3) = 177

r_{1, 2} = \frac{- ( - 9 ) \pm 177}{2 \cdot 8}

Separate the solutions

r_{1} = \frac{- ( - 9 ) + 177}{2 \cdot 8}, r_{2} = \frac{- ( - 9 ) - 177}{2 \cdot 8}

r = \frac{- ( - 9 ) + 177}{2 \cdot 8} : \frac{9 + 177}{16}

r = \frac{- ( - 9 ) - 177}{2 \cdot 8} : \frac{9 - 177}{16}

The solutions to the quadratic equation are:

r = \frac{9 + 177}{16}, r = \frac{9 - 177}{16}

0 = x (x + 9)

1625

m^{2} - 1

x^{3} - 3 x^{2} + x + 5

\frac{3 x ^{8} y ^{8}}{3 x ^{7} y}

What are the solutions to the equation 8r^2-9r-3=0 ?
The solutions to the equation 8r^2-9r-3=0 are r=(9+sqrt(177))/(16),r=(9-sqrt(177))/(16)
Find the zeros of 8r^2-9r-3=0
The zeros of 8r^2-9r-3=0 are r=(9+sqrt(177))/(16),r=(9-sqrt(177))/(16)