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Popular >

simplify e^{-ln(2)}*e^{-ln(s)}

Solution

simplify

e^{- l n (2)} \cdot e^{- l n (s)}

Solution

\frac{1}{2 s}

Solution steps

e^{- l n (2)} e^{- l n (s)}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- l n (2)} e^{- l n (s)} = e^{- l n (2) - l n (s)}

= e^{- l n (2) - l n (s)}

- ln (2) - ln (s) = - ln (2 s)

= e^{- l n (2 s)}

Apply exponent rule:

a^{b c} = (a^{b})^{c}

= (e^{l n (2 s)})^{- 1}

Apply log rule:

a^{l o g_{a} (b)} = b

e^{l n (2 s)} = 2 s

= (2 s)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{2 s}

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Frequently Asked Questions (FAQ)

What is e^{-ln(2)}*e^{-ln(s)} ?
The solution to e^{-ln(2)}*e^{-ln(s)} is 1/(2s)