What is (x^2+4x+4)^4(x-2)^4 ?

The solution to (x^2+4x+4)^4(x-2)^4 is (x-2)^4(x^2+4x+4)^4

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simplify (x^2+4x+4)^4(x-2)^4

simplify

(x^{2} + 4 x + 4)^{4} (x - 2)^{4}

(x - 2)^{4} (x^{2} + 4 x + 4)^{4}

Solution steps

(x^{2} + 4 x + 4)^{4} (x - 2)^{4}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} + 4 x + 4)^{4} (x - 2)^{4} = ((x^{2} + 4 x + 4) (x - 2))^{4}

= ((x^{2} + 4 x + 4) (x - 2))^{4}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x^{2} + 4 x + 4)^{4} (x - 2)^{4}

6 e^{- 4 y}

(e^{- 0.3}) (0.3)^{3}

x^{5} \cdot z^{5}

e^{- x} x^{4}

15 m n^{2.15} m

What is (x^2+4x+4)^4(x-2)^4 ?
The solution to (x^2+4x+4)^4(x-2)^4 is (x-2)^4(x^2+4x+4)^4