What is (\mid _{-5}^{2k})_{2}^k\mid ?

The solution to (\mid _{-5}^{2k})_{2}^k\mid is \mid ^{2k^2+1}

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simplify (\mid _{-5}^{2k})_{2}^k\mid

simplify

(∣_{- 5}^{2 k})_{2}^{k} ∣

∣^{2 k^{2} + 1}

Solution steps

(∣_{- 5}^{2 k})_{2}^{k} ∣

(∣_{- 5}^{2 k})_{2}^{k} : ∣^{2 k^{2}}

= ∣^{2 k^{2}} ∣

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

∣^{2 k^{2}} ∣ = ∣^{2 k^{2} + 1}

= ∣^{2 k^{2} + 1}

in f l e x i o n (x^{4} e^{- x})

x e^{- \frac{x}{3}}

\frac{9 ^{25}}{1 0 ^{25}}

1.3 \cdot (1 0^{- 9})

What is (\mid _{-5}^{2k})_{2}^k\mid ?
The solution to (\mid _{-5}^{2k})_{2}^k\mid is \mid ^{2k^2+1}