What are the solutions to the equation 4x^2=52 ?

The solutions to the equation 4x^2=52 are x=sqrt(13),x=-sqrt(13)

Find the zeros of 4x^2=52

The zeros of 4x^2=52 are x=sqrt(13),x=-sqrt(13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} = 52

x = 13, x = - 13

Decimal Notation

x = 3.60555 \dots, x = - 3.60555 \dots

Solution steps

4 x^{2} = 52

Divide both sides by

4

x^{2} = 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 13, x = - 13

0.01 (\frac{55 0 ^{3}}{3} - \frac{50 0 ^{3}}{3})

\frac{6}{7} + \frac{8}{9}

8 - 2 x^{2}

(x - 7)^{2} + x^{2} = (x + 1)^{2}

∣ x + 6 ∣ = 10

What are the solutions to the equation 4x^2=52 ?
The solutions to the equation 4x^2=52 are x=sqrt(13),x=-sqrt(13)
Find the zeros of 4x^2=52
The zeros of 4x^2=52 are x=sqrt(13),x=-sqrt(13)