What are the solutions to the equation 4x^2=52 ?

The solutions to the equation 4x^2=52 are x=sqrt(13),x=-sqrt(13)

Find the zeros of 4x^2=52

The zeros of 4x^2=52 are x=sqrt(13),x=-sqrt(13)

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4 x^{2} = 52

x = 13, x = - 13

Solution steps

4 x^{2} = 52

Divide both sides by

4

x^{2} = 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 13, x = - 13

0.01 (\frac{55 0 ^{3}}{3} - \frac{50 0 ^{3}}{3})

\frac{6}{7} + \frac{8}{9}

8 - 2 x^{2}

(x - 7)^{2} + x^{2} = (x + 1)^{2}

∣ x + 6 ∣ = 10

What are the solutions to the equation 4x^2=52 ?
The solutions to the equation 4x^2=52 are x=sqrt(13),x=-sqrt(13)
Find the zeros of 4x^2=52
The zeros of 4x^2=52 are x=sqrt(13),x=-sqrt(13)