What is (5x^{10}e^{-6})(4x^{10}e^{-5}) ?

The solution to (5x^{10}e^{-6})(4x^{10}e^{-5}) is (20x^{20})/(e^{11)}

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simplify (5x^{10}e^{-6})(4x^{10}e^{-5})

simplify

(5 x^{10} e^{- 6}) (4 x^{10} e^{- 5})

\frac{20 x ^{20}}{e ^{11}}

Solution steps

(5 x^{10} e^{- 6}) (4 x^{10} e^{- 5})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

e^{- 6} e^{- 5} = e^{- 6 - 5}

= 5 x^{10} \cdot 4 x^{10} e^{- 6 - 5}

Subtract the numbers:

- 6 - 5 = - 11

= 5 x^{10} \cdot 4 x^{10} e^{- 11}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{10} x^{10} = x^{10 + 10}

= 5 \cdot 4 x^{10 + 10} e^{- 11}

Add the numbers:

10 + 10 = 20

= 5 \cdot 4 x^{20} e^{- 11}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

e^{- 11} = \frac{1}{e ^{11}}

= 5 \cdot 4 \cdot \frac{1}{e ^{11}} x^{20}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 5 \cdot 4 x ^{20}}{e ^{11}}

Multiply the numbers:

1 \cdot 5 \cdot 4 = 20

= \frac{20 x ^{20}}{e ^{11}}

7 e^{3} \cdot 2 e^{2} \cdot (- 4) e

1.8 x 1 0^{- 6}

4.29 \cdot 1 0^{- 5}

(c + 1)^{3} (c - 1)^{3}

- \frac{35}{4} e^{- 4 \cdot 0.5}

What is (5x^{10}e^{-6})(4x^{10}e^{-5}) ?
The solution to (5x^{10}e^{-6})(4x^{10}e^{-5}) is (20x^{20})/(e^{11)}