What is x^2(x+3)(x-4)^2(x-5) ?

The solution to x^2(x+3)(x-4)^2(x-5) is x^2(x-4)^2(x+3)(x-5)

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simplify x^2(x+3)(x-4)^2(x-5)

simplify

x^{2} (x + 3) (x - 4)^{2} (x - 5)

x^{2} (x - 4)^{2} (x + 3) (x - 5)

Solution steps

x^{2} (x + 3) (x - 4)^{2} (x - 5)

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

x^{2} (x - 4)^{2} = (x (x - 4))^{2}

= (x (x - 4))^{2} (x + 3) (x - 5)

(x (x - 4))^{2} = x^{2} (x - 4)^{2}

= x^{2} (x - 4)^{2} (x + 3) (x - 5)

7.34 \cdot 1 0^{- 3}

e^{t} \cdot 3 e^{t}

1.99834 \cdot 1 0^{- 10}

k p k^{12} d an f p b^{20}

200 \cdot π (r)^{2} \cdot 4 r

What is x^2(x+3)(x-4)^2(x-5) ?
The solution to x^2(x+3)(x-4)^2(x-5) is x^2(x-4)^2(x+3)(x-5)