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Popular >

simplify (g^{-1}of^{-1})(pi/2)

Solution

simplify

(g^{- 1} o f^{- 1}) (\frac{π}{2})

Solution

\frac{π o}{2 g f}

Solution steps

(g^{- 1} o f^{- 1}) (\frac{π}{2})

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

g^{- 1} f^{- 1} = (g f)^{- 1}

= \frac{π}{2} o (g f)^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(g f)^{- 1} = \frac{1}{g f}

= \frac{π}{2} \cdot \frac{1}{g f} o

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 π o}{g f \cdot 2}

Multiply:

1 π = π

= \frac{π o}{2 g f}

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Frequently Asked Questions (FAQ)

What is (g^{-1}of^{-1})(pi/2) ?
The solution to (g^{-1}of^{-1})(pi/2) is (pio)/(2gf)