What is (-e^{-1x})(e^{-2x}) ?

The solution to (-e^{-1x})(e^{-2x}) is -1/(e^{3x)}

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simplify (-e^{-1x})(e^{-2x})

simplify

(- e^{- 1 x}) (e^{- 2 x})

- \frac{1}{e ^{3 x}}

Solution steps

(- e^{- 1 \cdot x}) (e^{- 2 x})

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2 x}} (- e^{- 1 \cdot x})

Remove parentheses:

(- a) = - a

= - e^{- 1 \cdot x} \frac{1}{e ^{2 x}}

Multiply:

1 \cdot x = x

= - e^{- x} \frac{1}{e ^{2 x}}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot e ^{- x}}{e ^{2 x}}

Multiply:

1 \cdot e^{- x} = e^{- x}

= - \frac{e ^{- x}}{e ^{2 x}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

\frac{e ^{- x}}{e ^{2 x}} = e^{- x - 2 x} = e^{- 3 x}

= - \frac{1}{e ^{3 x}}

(6.54 \cdot 1 0^{- 4}) (9) (9.8)

4.5 e^{- 5}

3.75 \cdot 1 0^{- 1}

- 0.004 e^{- 0.004 (100)}

\frac{t + 9}{t - 9}

What is (-e^{-1x})(e^{-2x}) ?
The solution to (-e^{-1x})(e^{-2x}) is -1/(e^{3x)}